A <xsl:copy-of select="."/> will select the concatenated text of all
descendant text-nodes in document-order; note the additional "don't" in
the result:
<output>"Johnny
don't
B.
Good
"</output>
No, copy-of literally copies the selected nodes. If you select text(), it copies all text child
nodes of the current node. If you select ., it copies the current node itself, including its start
and end tag and all it's descendants, resulting in:
<output>"<foo>Johnny
<bar>don't</bar>
B.
<bar/>Good
</foo>"</output>
MSXML does strip such whitespace text-nodes by _default_. So one might
want to use <xsl:strip-space elements="*"/> for compatibility with
the MSXML-XSLT engine.
Or just use <xsl:preserve-space elements="*" /> when using MSXSL to make it comply with the other
parsers.. :-)
Kind regards,
Geert
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