I try to get the Application name. but i didnt get any
ouptut..
what is wrong here?
The xsl:for-each-group instruction:
<xsl:for-each-group select="Application"
group-by="Application">
will not select anything, because in your source xml document an
"Application" element does not have "Application" children.
--
Cheers,
Dimitre Novatchev
---------------------------------------
Truly great madness cannot be achieved without significant intelligence.
On 3/29/06, Arulraj <p_arulraj(_at_)yahoo(_dot_)com> wrote:
Hello List,
I am using the following XML input sequence,
<?xml version="1.0" encoding="UTF-8"?>
<layout>
<Application name="odcs2web">
<Processgroup name="FSRenta">
<Process name="sample">
<PanelName name="H2WSearchLayout"/>
<PanelName name="H2WListAllLayout"/>
<PanelName name="H2WEditLayout"/>
<PanelName name="H2WNewLayout"/>
</Process>
<Process name="sampleflowinfo">
<PanelName name="H2WListFlowInfo"/>
<PanelName name="H2WAddFlowInfo"/>
<PanelName name="H2WUpdFlowInfo"/>
<PanelName name="H2WDelFlowInfo"/>
</Process>
</Processgroup>
</Application>
<Application name="bvwinfo">
<Processgroup name="bvwinfogrp">
<Process name="bvw1">
<PanelName name="screen1"/>
</Process>
<Process name="bvw2">
<PanelName name="screen2"/>
</Process>
</Processgroup>
</Application>
</layout>
And XSLT.. i have the following code.
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:template match="layout">
<xsl:for-each-group select="Application"
group-by="Application">
<xsl:value-of
select="current-group()/@name"/>
</xsl:for-each-group>
</xsl:template>
I try to get the Application name. but i didnt get any
ouptut..
what is wrong here?
regards,
Arul
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