Difficult to know what to advise since you don't explain what output you are
trying to achieve. Your logic is clearly wrong as Dimitre points out, but
I've no idea what you had in mind.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Arulraj [mailto:p_arulraj(_at_)yahoo(_dot_)com]
Sent: 29 March 2006 07:30
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] for-each-group in xslt 2.0
Hello List,
I am using the following XML input sequence,
<?xml version="1.0" encoding="UTF-8"?>
<layout>
<Application name="odcs2web">
<Processgroup name="FSRenta">
<Process name="sample">
<PanelName name="H2WSearchLayout"/>
<PanelName name="H2WListAllLayout"/>
<PanelName name="H2WEditLayout"/>
<PanelName name="H2WNewLayout"/>
</Process>
<Process name="sampleflowinfo">
<PanelName name="H2WListFlowInfo"/>
<PanelName name="H2WAddFlowInfo"/>
<PanelName name="H2WUpdFlowInfo"/>
<PanelName name="H2WDelFlowInfo"/>
</Process>
</Processgroup>
</Application>
<Application name="bvwinfo">
<Processgroup name="bvwinfogrp">
<Process name="bvw1">
<PanelName name="screen1"/>
</Process>
<Process name="bvw2">
<PanelName name="screen2"/>
</Process>
</Processgroup>
</Application>
</layout>
And XSLT.. i have the following code.
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:template match="layout">
<xsl:for-each-group select="Application"
group-by="Application">
<xsl:value-of
select="current-group()/@name"/>
</xsl:for-each-group>
</xsl:template>
I try to get the Application name. but i didnt get any
ouptut..
what is wrong here?
regards,
Arul
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