Re: [xsl] for-each-group in xslt 2.0

ok thanks..

if i use 
<xsl:for-each-group select="." group-by="Application">

i got the correct result.

regards,
Arul
--- Dimitre Novatchev <dnovatchev(_at_)gmail(_dot_)com> wrote:

I try to get the Application name. but i didnt get

any

ouptut..
what is wrong here?


The xsl:for-each-group instruction:

         <xsl:for-each-group select="Application"
group-by="Application">


will not select anything, because in your source xml
document an
"Application" element does not have "Application"
children.


--
Cheers,
Dimitre Novatchev
---------------------------------------
Truly great madness cannot be achieved without
significant intelligence.


On 3/29/06, Arulraj <p_arulraj(_at_)yahoo(_dot_)com> wrote:

Hello List,

I am using the following XML input sequence,
 <?xml version="1.0" encoding="UTF-8"?>
 <layout>
     <Application name="odcs2web">
         <Processgroup name="FSRenta">
             <Process name="sample">
                 <PanelName

name="H2WSearchLayout"/>

                 <PanelName

name="H2WListAllLayout"/>

                 <PanelName name="H2WEditLayout"/>
                 <PanelName name="H2WNewLayout"/>
             </Process>
             <Process name="sampleflowinfo">
                 <PanelName

name="H2WListFlowInfo"/>

                 <PanelName

name="H2WAddFlowInfo"/>

                 <PanelName

name="H2WUpdFlowInfo"/>

                 <PanelName

name="H2WDelFlowInfo"/>

             </Process>
         </Processgroup>
     </Application>
     <Application name="bvwinfo">
         <Processgroup name="bvwinfogrp">
             <Process name="bvw1">
                 <PanelName name="screen1"/>
             </Process>
             <Process name="bvw2">
                 <PanelName name="screen2"/>
             </Process>
         </Processgroup>
     </Application>
 </layout>

 And XSLT.. i have the following code.

 <?xml version="1.0" encoding="ISO-8859-1"?>
 <xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
     <xsl:template match="layout">
         <xsl:for-each-group select="Application"
group-by="Application">
                 <xsl:value-of
select="current-group()/@name"/>
         </xsl:for-each-group>
       </xsl:template>

I try to get the Application name. but i didnt get

any

ouptut..
what is wrong here?

regards,
Arul

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