Hello,
I have two questions:
1) If I have an XML input file like this:
<root>
<Text>
<junk>xxx</junk>
<tag>Als die ersten Städte zu einer Größe
heranwuchsen</tag>
<junk2>xxx</junk2>
</Text>
</root>
I would like to skip the <junk> only transform the <tag>; however the output
shall still have the special character as it is there in the input file.
Unfortunately the special characters get translated into the proper German
characters.
That is:
<root>
<Text>
<tag>Als die ersten Städte zu einer Größe heranwuchsen</tag>
</Text>
</root>
This is my XSLT:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="text" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="/">
<xsl:element name="root">
<xsl:for-each select="Text">
<xsl:element name="Text">
<xsl:element name="tag">
<xsl:value-of select="tag"/>
</xsl:element>
</xsl:element>
</xsl:for-each>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
How can I avoid it?
2) If I had a namespace on the root:
<root xmlns="http://www.fo.com";>
<Text>
<junk>xxx</junk>
<tag>Als die ersten Städte zu einer Größe
heranwuchsen</tag>
<junk2>xxx</junk2>
</Text>
</root>
The way I do it (not shown here) is that I get the namespace behind each single
tag. But how do I modify my XSL so that the output is like this:
<root xmlns="http://www.fo.com";>
<Text>
<tag>Als die ersten Städte zu einer Größe
heranwuchsen </tag>
</Text>
</root>
Many Thanks for help,
Houman
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