Sorry, the sample I am using is more complicated than the one I have shown
here. I made a mistake. In real the root has children.
My problem here is the for-each statement
<xsl:for-each select="root/TEXT">
Because root has a namespace:
<root xmlns="http://www.foo.com";>
So I have to make my for-each element to understand that the "root" with the
following namespace has a "TEXT" tag. But I don't know yet how...
Thanks for the references, I will have a look and hopefully find something.
That should be straight forward...
Thanks
Houman
-----Original Message-----
From: Florent Georges [mailto:darkman_spam(_at_)yahoo(_dot_)fr]
Sent: 05 May 2006 11:33
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] Special characters and Transformation
"Khorasani, Houman" wrote:
2) For some reason I can't even reproduce the problem.
I only get a root with namespace and all elements are
empty underneath.
I tried this:
<?xml version="1.0" encoding="us-ascii"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="xml" version="1.0" encoding="us-ascii"
indent="yes"/>
<xsl:template match="/">
<xsl:element name="root" namespace="http://www.fo.com";>
<xsl:for-each select="Text">
<xsl:element name="Text">
<xsl:element name="tag">
<xsl:value-of select="tag"/>
</xsl:element>
</xsl:element>
</xsl:for-each>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
You don't have any 'Text' children of your root node (in the sample
you provided). Use instead:
<xsl:for-each select="root/Text">
BTW, I suggest you to take a look at "Literal Result Elements",
"Template Rules", and maybe the "Modified Identity Tranformation
Pattern".
Regards,
--drkm
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