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RE: [xsl] Sort before paging

2006-08-27 05:03:55

[italian error]
Il foglio di stile non include un elemento documento. Il 
foglio di stile è vuoto oppure potrebbe essere un documento 
XML in formato non corretto. 

[english error]
The stylesheet does not iclude a valid element. The 
stylesheet is empty or it should be a not valid xml document 
with a correct format.

From my limited Italian, it's actually complaining that there isn't a
"document element", that is, an element that contains all the others. You
seem to have left out the xsl:stylesheet element. Remember that stylesheets
must be valid XML documents.

Michael Kay
http://www.saxonica.com/


Code
-------------------------------------
<xsl:param name="start" select="1"/>
<xsl:param name="range" select="5"/>
<xsl:template match="/">
<xsl:call-template name="positionfilter"> <xsl:with-param 
name="sortedlist"> <xsl:for-each 
select="/CommandList/CheckRouting/RouterList/Router/GroupList/
Group/OutwardL
ist/Outward[position() &gt;=$start and position() &lt; $start 
+ $range]" > <xsl:sort select="Price/Amount" 
data-type="number" order="ascending" /> <xsl:copy-of 
select="."/> </xsl:for-each> </xsl:with-param> 
</xsl:call-template/> </xsl:template>


<xsl:template name="positionfilter">
<xsl:param name="sortedlist"/>
<xsl:for-each select="$sortedlist/*[(position() &gt;= $start) and
(position() &lt; $start + $range)]">
'my code
</xsl:for-each>
</xsl:template>

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