Re: [xsl] Sort before paging

The code have all the stylesheet tags.

So it seems be a well format xml

But it goes on error the same:


I try with this one...
But it doesn't works.

<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; >
<xsl:output method="html" indent="yes"/>

<xsl:param name="start" select="1"/>
<xsl:param name="range" select="5"/>
<xsl:template match="/">
<xsl:call-template name="positionfilter">
<xsl:with-param name="sortedlist">
<xsl:for-each
select="/CommandList/CheckRouting/RouterList/Router/GroupList/Group/OutwardL
ist/Outward[position() &gt;=$start and position() &lt; $start + $range]" >
<xsl:sort select="Price/Amount" data-type="number" order="ascending" />
<xsl:copy-of select="."/>
</xsl:for-each>
</xsl:with-param>
</xsl:call-template/>
</xsl:template>


<xsl:template name="positionfilter">
<xsl:param name="sortedlist"/>
<xsl:for-each select="$sortedlist/*[(position() &gt;= $start) and
(position() &lt; $start + $range)]">
'my code
</xsl:for-each>
</xsl:template>


</xsl:stylesheet> 


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