If I needed to perform a sort on x and y1 first, could I do it in the same
stylesheet?
The solution I provided doesn't require any sort.
--
Cheers,
Dimitre Novatchev
---------------------------------------
Truly great madness cannot be achieved without significant intelligence.
---------------------------------------
To invent, you need a good imagination and a pile of junk
-------------------------------------
You've achieved success in your field when you don't know whether what
you're doing is work or play
On 2/3/07, Simon Shutter <simon(_at_)schemax(_dot_)com> wrote:
That's brilliant Andrew.
If I needed to perform a sort on x and y1 first, could I do it in the same
stylesheet?
Simon
-----Original Message-----
From: Andrew Welch [mailto:andrew(_dot_)j(_dot_)welch(_at_)gmail(_dot_)com]
Sent: February 3, 2007 1:59 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Calculating cumulative values
On 2/3/07, Simon Shutter <simon(_at_)schemax(_dot_)com> wrote:
> Hello,
>
> Here is a tricky (to me) problem that requires looping over several
> sets and calculating cumulative values (y2) from x and y1. That is,
> for each x, set
> y2 to be equal to the cumulative value of y1 as shown in the example
> output below.
>
> I made my best attempt with the stylesheet below, which I know is
> quite incorrect but wanted to show I did actually try to solve the
> problem. I am now bogged down with the use of the variable element.
>
> Any assistance would be greatly appreciated,
>
> Simon
>
> ---------------------------------------------
> Input
> ---------------------------------------------
>
> <root id="theroot">
> <set id="1">
> <point x="1" y1="2" />
> <point x="1" y1="3" />
> <point x="1" y1="0" />
> <point x="1" y1="2" />
> <point x="1" y1="2" />
> <point x="2" y1="3" />
> <point x="2" y1="0" />
> <point x="2" y1="2" />
> <point x="3" y1="2" />
> <point x="3" y1="3" />
> <point x="3" y1="1" />
> <point x="3" y1="2" />
> <point x="3" y1="2" />
> </set>
> <set id="2">
> <point x="1" y1="2" />
> <point x="1" y1="3" />
> <point x="1" y1="0" />
> <point x="1" y1="2" />
> <point x="2" y1="2" />
> <point x="3" y1="2" />
> <point x="3" y1="2" />
> <point x="3" y1="2" />
> </set>
> <set id="n">
> <point x="1" y1="2" />
> <point x="1" y1="3" />
> <point x="1" y1="2" />
> <point x="2" y1="3" />
> <point x="2" y1="0" />
> <point x="2" y1="2" />
> <point x="3" y1="3" />
> </set>
> </root>
>
> ---------------------------------------------
> Desired output
> ---------------------------------------------
> <root id="theroot">
> <set id="1">
> <point x="1" y1="2" y2="2"/>
> <point x="1" y1="3" y2="5"/>
> <point x="1" y1="0" y2="5"/>
> <point x="1" y1="2" y2="7"/>
> <point x="1" y1="2" y2="9"/>
> <point x="2" y1="3" y2="3"/>
> <point x="2" y1="0" y2="3"/>
> <point x="2" y1="2" y2="5"/>
> <point x="3" y1="2" y2="2"/>
> <point x="3" y1="3" y2="5"/>
> <point x="3" y1="1" y2="6"/>
> <point x="3" y1="2" y2="8"/>
> <point x="3" y1="2" y2="10"/>
> </set>
> <set id="2">
> <point x="1" y1="2" y2="2"/>
> <point x="1" y1="3" y2="5"/>
> <point x="1" y1="0" y2="5"/>
> <point x="1" y1="2" y2="7"/>
> <point x="2" y1="2" y2="2"/>
> <point x="3" y1="2" y2="2"/>
> <point x="3" y1="2" y2="4"/>
> <point x="3" y1="2" y2="6"/>
> </set>
> <set id="n">
> <point x="1" y1="2" y2="2"/>
> <point x="1" y1="3" y2="5"/>
> <point x="1" y1="2" y2="7"/>
> <point x="2" y1="3" y2="3"/>
> <point x="2" y1="0" y2="3"/>
> <point x="2" y1="2" y2="5"/>
> <point x="3" y1="3" y2="3"/>
> </set>
> </root>
>
> ---------------------------------------------
> Prototype stylesheet - just to show I tried
> ---------------------------------------------
> <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
> <xsl:variable name="tempy" select="5"/>
> <!-- Convert root and all elements tags 'as is' --> <xsl:template
> match="@*|node()">
> <xsl:copy>
> <xsl:apply-templates select="@*|node()"/>
> </xsl:copy>
> </xsl:template>
> <xsl:template match="//point">
> <xsl:copy>
> <xsl:copy-of select="@*"/>
> <xsl:for-each select="@y1">
> <xsl:attribute name="y2">
> <xsl:choose>
> <xsl:when test=". > $tempy">
> <xsl:value-of select="$tempy * ."/>
> </xsl:when>
> <xsl:otherwise>
> <xsl:value-of select="$tempy + ."/>
> </xsl:otherwise>
> </xsl:choose>
> </xsl:attribute>
> </xsl:for-each>
> </xsl:copy>
> </xsl:template>
> </xsl:stylesheet>
You can just use XPath here, no need for recursion:
<xsl:template match="point">
<xsl:copy>
<xsl:copy-of select="@*"/>
<xsl:attribute name="y2">
<xsl:value-of select="sum(./@y1|preceding-sibling::point[(_at_)x =
current()/@x]/@y1)"/>
</xsl:attribute>
</xsl:copy>
</xsl:template>
cheers
andrew
--~------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--
--~------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--
--~------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--