Thanks, Dimitre - I'll try that
-----Original Message-----
From: Dimitre Novatchev [mailto:dnovatchev(_at_)gmail(_dot_)com]
Sent: February 4, 2007 7:20 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Calculating cumulative values
If I needed to sort the data before I determined the cumulative
numbers, how do I ensure this happens before aggregating the data?
This is a well-known technique, which requires the use of (in your case
msxsl:node-set() ) the extension function exsl:node-set() or the
XSLT-processor-implemented xxx:node-set() extension function.
A smal blueprint is below:
<xsl:variable name="vrtfOtputTree">
<!-- Whatever processing required to produce a new tree -->
</xsl:variable>
<xsl:variable name="vOutputTree" select="xxx:node-set($vrtfOtputTree)"/>
<!-- Then continue with using the temporary tree that was obtained from the
RTF -->
<!-- For example: -->
<xsl:value-of select="$vOutputTree/*/*[1]"/>
Of course, one can use FXSL for XSLT 1.0 and use the same approach, shown in
the FXSL 2.0 solution.
--
Cheers,
Dimitre Novatchev
---------------------------------------
Truly great madness cannot be achieved without significant intelligence.
---------------------------------------
To invent, you need a good imagination and a pile of junk
-------------------------------------
You've achieved success in your field when you don't know whether what
you're doing is work or play
On 2/3/07, Simon Shutter <simon(_at_)schemax(_dot_)com> wrote:
I think I may go with 'conventional' solution provided by Andrew, because
it
is natively supported by .Net 2 and my data sets are relatively small and
tranformed pretty quickly. I will look more into FXSL for the longer
term.
If I needed to sort the data before I determined the cumulative numbers,
how
do I ensure this happens before aggregating the data?
Thanks,
Simon
-----Original Message-----
From: Dimitre Novatchev [mailto:dnovatchev(_at_)gmail(_dot_)com]
Sent: February 3, 2007 4:48 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Calculating cumulative values
On 2/3/07, Simon Shutter <simon(_at_)schemax(_dot_)com> wrote:
Thanks, Dimitre.
Two questions -
a) Will this work with .Net 2.0?
No, the two XSLT processors that come as part of .NET 2.0 (the classes
XslTransform and XslCompiledTransform) only support XSLT 1.0.
However, in a .NET environment one can use Saxon.NET, which is a port of
Saxon 8.x and implements XSLT 2.0.
b) What are the external files : func-scanlDVC.xsl and
func-Operators.xsl?
They are part of the FXSL library.
The latest version of FXSL can be checked out from the CVS of the project
at:
http://sourceforge.net/cvs/?group_id=53841
One can learn more about FXSL from the presentations made at the Extreme
Markup Languages Conference in Montreal 2006 (FXSL 2 -- for XSLT 2.0, and
FXSL 1 -- for XSLT 1.0) here:
http://www.idealliance.org/papers/extreme/proceedings/xslfo-pdf/2006/Novatch
ev01/EML2006Novatchev01.pdf
and here:
http://www.idealliance.org/papers/extreme/proceedings/xslfo-pdf/2003/Novatch
ev01/EML2003Novatchev01.pdf
Other papers about different important features of FXSL can be found at
the
home page of FXSL:
http://fxsl.sf.net
--
Cheers,
Dimitre Novatchev
---------------------------------------
Truly great madness cannot be achieved without significant intelligence.
---------------------------------------
To invent, you need a good imagination and a pile of junk
-------------------------------------
You've achieved success in your field when you don't know whether what
you're doing is work or play
Simon
-----Original Message-----
From: Dimitre Novatchev [mailto:dnovatchev(_at_)gmail(_dot_)com]
Sent: February 3, 2007 2:50 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Calculating cumulative values
On 2/3/07, Andrew Welch <andrew(_dot_)j(_dot_)welch(_at_)gmail(_dot_)com>
wrote:
You can just use XPath here, no need for recursion:
<xsl:template match="point">
<xsl:copy>
<xsl:copy-of select="@*"/>
<xsl:attribute name="y2">
<xsl:value-of select="sum(./@y1|preceding-sibling::point[(_at_)x =
current()/@x]/@y1)"/>
</xsl:attribute>
</xsl:copy>
</xsl:template>
However evaluating this XPath expression repeatedly is O(N^2) and will
probably be slow for long lists.
Here is a solution, using the FXSL function
f:scanl1()
This transformation:
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:f="http://fxsl.sf.net/";
exclude-result-prefixes="f"
<xsl:import href="../f/func-scanlDVC.xsl"/>
<xsl:import href="../f/func-Operators.xsl"/>
<!-- To be applied on testFunc-scanlDVC3.xml -->
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="set">
<xsl:copy>
<xsl:copy-of select="@*"/>
<xsl:for-each-group select="point" group-by="@x">
<xsl:for-each select="f:scanl1(f:add(), current-group()/@y1)">
<point x="{current-group()[1]/@x}" y="{.}"/>
</xsl:for-each>
</xsl:for-each-group>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
When applied against the originally provided xml document:
<root id="theroot">
<set id="1">
<point x="1" y1="2" />
<point x="1" y1="3" />
<point x="1" y1="0" />
<point x="1" y1="2" />
<point x="1" y1="2" />
<point x="2" y1="3" />
<point x="2" y1="0" />
<point x="2" y1="2" />
<point x="3" y1="2" />
<point x="3" y1="3" />
<point x="3" y1="1" />
<point x="3" y1="2" />
<point x="3" y1="2" />
</set>
<set id="2">
<point x="1" y1="2" />
<point x="1" y1="3" />
<point x="1" y1="0" />
<point x="1" y1="2" />
<point x="2" y1="2" />
<point x="3" y1="2" />
<point x="3" y1="2" />
<point x="3" y1="2" />
</set>
<set id="n">
<point x="1" y1="2" />
<point x="1" y1="3" />
<point x="1" y1="2" />
<point x="2" y1="3" />
<point x="2" y1="0" />
<point x="2" y1="2" />
<point x="3" y1="3" />
</set>
</root>
produces the wanted result:
<root id="theroot">
<set id="1">
<point x="1" y="2"/>
<point x="1" y="5"/>
<point x="1" y="5"/>
<point x="1" y="7"/>
<point x="1" y="9"/>
<point x="2" y="3"/>
<point x="2" y="3"/>
<point x="2" y="5"/>
<point x="3" y="2"/>
<point x="3" y="5"/>
<point x="3" y="6"/>
<point x="3" y="8"/>
<point x="3" y="10"/>
</set>
<set id="2">
<point x="1" y="2"/>
<point x="1" y="5"/>
<point x="1" y="5"/>
<point x="1" y="7"/>
<point x="2" y="2"/>
<point x="3" y="2"/>
<point x="3" y="4"/>
<point x="3" y="6"/>
</set>
<set id="n">
<point x="1" y="2"/>
<point x="1" y="5"/>
<point x="1" y="7"/>
<point x="2" y="3"/>
<point x="2" y="3"/>
<point x="2" y="5"/>
<point x="3" y="3"/>
</set>
</root>
--
Cheers,
Dimitre Novatchev
---------------------------------------
Truly great madness cannot be achieved without significant intelligence.
---------------------------------------
To invent, you need a good imagination and a pile of junk
-------------------------------------
You've achieved success in your field when you don't know whether what
you're doing is work or play
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