Thanks, Andrew
I'm relatively new to XML. If I want to apply your converter, what input
file do I give the processor?
Simon
-----Original Message-----
From: Andrew Welch [mailto:andrew(_dot_)j(_dot_)welch(_at_)gmail(_dot_)com]
Sent: February 13, 2007 8:59 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Transforming tabular information to hierarchical
On 2/13/07, Simon Shutter <simon(_at_)schemax(_dot_)com> wrote:
If I have a tabular data set that defines parent-child relationships,
is it possible to transform this into a hierarchical tree format using
XSLT?
Here's a csv to XML converter I wrote the other day, feel free to convert it
to use tabs, or adjust your input to be comma delimited.
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
exclude-result-prefixes="xs">
<xsl:output indent="yes" encoding="US-ASCII"/>
<xsl:param name="pathToCSV" select="'file:///c:/temp/test.csv'"/>
<xsl:template name="main">
<xsl:choose>
<xsl:when test="unparsed-text-available($pathToCSV)">
<xsl:variable name="csv"
select="unparsed-text($pathToCSV)"/>
<xsl:variable name="lines" select="tokenize($csv,
'
')" as="xs:string+"/>
<xsl:variable name="elemNames"
select="tokenize($lines[1], ',')"
as="xs:string+"/>
<root>
<xsl:for-each select="$lines[position() >
1]">
<row>
<xsl:variable
name="lineItems"
select="tokenize(normalize-space(.), ',')" as="xs:string+"/>
<xsl:for-each
select="$elemNames">
<xsl:variable
name="pos" select="position()"/>
<xsl:element
name="{normalize-space(.)}">
<xsl:value-of select="$lineItems[$pos]"/>
</xsl:element>
</xsl:for-each>
</row>
</xsl:for-each>
</root>
</xsl:when>
<xsl:otherwise>
<xsl:text>Cannot locate : </xsl:text><xsl:value-of
select="$pathToCSV"/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
</xsl:stylesheet>
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