On 2/13/07, Simon Shutter <simon(_at_)schemax(_dot_)com> wrote:
If I have a tabular data set that defines parent-child relationships, is it
possible to transform this into a hierarchical tree format using XSLT?
Here's a csv to XML converter I wrote the other day, feel free to
convert it to use tabs, or adjust your input to be comma delimited.
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
exclude-result-prefixes="xs">
<xsl:output indent="yes" encoding="US-ASCII"/>
<xsl:param name="pathToCSV" select="'file:///c:/temp/test.csv'"/>
<xsl:template name="main">
<xsl:choose>
<xsl:when test="unparsed-text-available($pathToCSV)">
<xsl:variable name="csv"
select="unparsed-text($pathToCSV)"/>
<xsl:variable name="lines" select="tokenize($csv, '
')"
as="xs:string+"/>
<xsl:variable name="elemNames" select="tokenize($lines[1],
',')"
as="xs:string+"/>
<root>
<xsl:for-each select="$lines[position() > 1]">
<row>
<xsl:variable name="lineItems"
select="tokenize(normalize-space(.), ',')" as="xs:string+"/>
<xsl:for-each
select="$elemNames">
<xsl:variable name="pos"
select="position()"/>
<xsl:element
name="{normalize-space(.)}">
<xsl:value-of
select="$lineItems[$pos]"/>
</xsl:element>
</xsl:for-each>
</row>
</xsl:for-each>
</root>
</xsl:when>
<xsl:otherwise>
<xsl:text>Cannot locate : </xsl:text><xsl:value-of
select="$pathToCSV"/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
</xsl:stylesheet>
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