I thought REassignment is not possible in XSLT.
It seems what I am doing is veery similar to what is
going on in this FAQ:
http://www.dpawson.co.uk/xsl/sect2/N8090.html#d11742e181
I do not see how my code is different than this:
<xsl:variable name="x">
<xsl:choose>
<xsl:when test="a">z</xsl:when>
<xsl:when test="b">zz</xsl:when>
<xsl:otherwise>zzz</xsl:otherwise>
</xsl:choose>
</xsl:variable>
____________________________________________________________________________________
Finding fabulous fares is fun.
Let Yahoo! FareChase search your favorite travel sites to find flight and hotel
bargains.
http://farechase.yahoo.com/promo-generic-14795097
--~------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--