XQuery is actually off-topic for this list, but I didn't notice that when
you started the thread because your subject line says XPath.
With Saxon-SA 8.9.0.3,
(1) it reports the error "function is in a reserved namespace". Function
names must be in your own namespace.
(2) When I fix that (prefix the function name with "local:"), it works fine.
I think there is a bug in your XQuery processor.
Michael Kay
-----Original Message-----
From: v vijith [mailto:vvijith(_at_)gmail(_dot_)com]
Sent: 22 July 2007 03:42
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Finding the ID attribute of an XPath from XMLSchema
Mike
Based on the syntax above, I wrote the code and gives an
error, context document undefined.
declare function id-from-element ( $element as element()? )
as xs:string? {
data(($element/@*[id(.) is ..])[1]) } ;
let $dm := doc("/repository/content/3001") let $ee:=
id-from-element($dm//figure/picture[1])
return
<net>
{$ee}
</net>
It gives me an error "context document undefined".
the XML is having the struct
<?xml version="1.0" encoding="UTF-8"?>
<sample1 xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance";
xsi:noNamespaceSchemaLocation="sample1.xsd">
<data>Copyright MyCompany 2007</data>
<figure>
<picture no="IMAGE-1"/>
<picture no="IMAGE-2"/>
<picture no="IMAGE-3"/>
</figure>
</sample1>
XSD is
<?xml version="1.0" encoding="UTF-8"?>
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema";
elementFormDefault="qualified">
<xs:element name="sample1">
<xs:complexType>
<xs:sequence>
<xs:element ref="data"/>
<xs:element ref="figure"/>
</xs:sequence>
</xs:complexType>
</xs:element>
<xs:element name="data" type="xs:string"/>
<xs:element name="figure">
<xs:complexType>
<xs:sequence>
<xs:element
maxOccurs="unbounded" ref="picture"/>
</xs:sequence>
</xs:complexType>
</xs:element>
<xs:element name="picture">
<xs:complexType>
<xs:attribute name="no" use="required"
type="xs:ID"/>
</xs:complexType>
</xs:element>
</xs:schema>
Thanks
Vijith
On 7/21/07, Michael Kay <mike(_at_)saxonica(_dot_)com> wrote:
Given a node $n, you can find the value of its ID attribute
if it has
one using
$n/@*[id(.) is $n]
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: v vijith [mailto:vvijith(_at_)gmail(_dot_)com]
Sent: 21 July 2007 19:16
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Finding the ID attribute of an XPath from
XMLSchema
Below is a snippet from the XMLSchema
<xs:complexType name="nameType">
<xs:sequence>
<xs:element minOccurs="0" ref="desig"/>
</xs:sequence>
<xs:attribute ref="dest" use="required"/>
<xs:attribute ref="id"/>
<xs:attribute ref="garageid"/>
<xs:attributeGroup ref="xlink:XLINKATT1"/>
</xs:complexType>
<xs:attribute name="id" type="xs:ID"/>
this means that in the XML, the nameType node can be
identified by
the id attribute as xs:attribute name=id is mapped to XS:ID.
Likewise there can be many nodes in the XML that has ID
associated
to it.
<xml>
<root>
<somenode>
<nameType id="2" attrib2="34">text</nameType> <nameType id="3"
attrib2="34">text</nameType> <nameType id="4"
attrib2="34">text</nameType> </somenode> <anothernode
attrib5="55"/>
</root>
In the XML, I perform some kind of XQuery and I get the output as
root/somenode/anothernode/nameType.
Once I get this node, I should be able to find if there is an ID
attribute defined for this node in the XSD.
In the above case, the id attribute in the nameType tag is the
attribute as per the XML Schema.
So I need the output as id for the xpath
root/somenode/anothernode/nameType
Hope I have explained it better!
Well what I thought was this way as a solution 1. Parse the
XMLSchema 2. Make a map of XPath as key and the id as attribute.
3. Once I get the xpath from xquery, check the map to
find the id 4.
But parsing XMLSchema and mapping is not that simple either
Thanks
Vijith
On 7/21/07, Michael Kay <mike(_at_)saxonica(_dot_)com> wrote:
I have an XML which is associated to an XMLSchema. Once I
perform an
XQuery on the XML I get a selected set of XPaths (Im
using our own
functions).
For each XPath I need to know what is the ID attribute
for the XPath.
I know that in XMLSchema there is an XS:ID Attribute. I
would like
to know if there is a way to find the ID associated from the
XMLSchema for an XPath in the XML.
Did I confuse everyone?
You certainly confused me. Show us your source document
and tell
us what you want your output to look like.
Michael Kay
http://www.saxonica.com/
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