[xsl] Finding the current node type

Hi Kamal

Thanks for the tip. It worked but for some reason the namespace prefix
is not part of the node name:

For example, I have <abc:code>1234</abc:code>

Local-name returns "code"

I can work without the namespace prefix, just struck me as being a bit
strange.


> If I understand what you are trying to do, you could use local-name(). 
> This will give you the name of the node.
Regards

Mark

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