Re: [xsl] escaping ampersands in replace function

I'm using XSLT2's replace function against a string but am having problems
escaping the ampersand.


ampersaand isn't a special character to xpath regular expressions, so
you don't need to escape it  so you want:

replace($l_TempString,'&','and')

then you need to put that XPath expression in a slect attribute,
whenever you put a string containg & in an XMl file you need to write it
as &amp; so the xslt looks like

select="replace($l_TempString,'&amp;','and')"

This is assuming that your input string contains a " & " 
 if it contains " &amp; "
then you want the XPath


replace($l_TempString,'&amp;','and')


which would be written in an XML file such as an XSLT stylesheet as

select="replace($l_TempString,'&amp;amp;','and')"

as the & has to be written as &amp;

David

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