Re: [xsl] escaping ampersands in replace function

Sorry to say

replace($l_TempString,'&','and')
get an error message stating the & must be followed by an entity reference

replace($l_TempString,'&amp;','and') and 
replace($l_TempString,'&amp;amp;','and')
the amp is not replaced.

I'm using the latest version of Saxon8 (from sourceforge).

An example of a string I'm trying to replace: A &amp; B to A and B. So the
process I'm using is get only the string values of a node's descendants into a
var (l_TempString), then create a new variable with a replace statement. Maybe
my method is incorrect.

Marijan (Mario) Madunic




Quoting David Carlisle <davidc(_at_)nag(_dot_)co(_dot_)uk>:

I'm using XSLT2's replace function against a string but am having problems
escaping the ampersand.


ampersaand isn't a special character to xpath regular expressions, so
you don't need to escape it  so you want:

replace($l_TempString,'&','and')

then you need to put that XPath expression in a slect attribute,
whenever you put a string containg & in an XMl file you need to write it
as &amp; so the xslt looks like

select="replace($l_TempString,'&amp;','and')"

This is assuming that your input string contains a " & " 
 if it contains " &amp; "
then you want the XPath


replace($l_TempString,'&amp;','and')


which would be written in an XML file such as an XSLT stylesheet as

select="replace($l_TempString,'&amp;amp;','and')"

as the & has to be written as &amp;

David

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