Re: [xsl] escaping ampersands in replace function

Not all fragments will contain an &amp;. Franklin &amp; Jefferson will still be
output as Franklin &amp; Jefferson and not Franklin and Jefferson

here is an XML fragment

<bodyContent>
<p>Tagged the World of Franklin &amp; Jefferson," display was created by general
Charles and Ray Eames fof the American Revolution centennial Administration, a
ernment organization</p>
<p>Show will go on to Warsaw and London, then proceed to the Museum of Modern
Art in N.Y. Later it is to be exhibited in Chicago and San Francisco.</p>
</bodyContent>

the XSLT fragment

<xsl:variable name="l_TempBodyContent">
<xsl:for-each select="body/node()">
<xsl:choose>
<xsl:when test="position() = 1"><xsl:value-of select="." /></xsl:when>
<xsl:otherwise><xsl:value-of select="concat(' ', .)" /></xsl:otherwise>
</xsl:choose>
</xsl:for-each>
</xsl:variable>

<xsl:variable name="l_BodyContent" select="replace($l_TempBodyContent, '&amp;',
'and')" />

Marijan (Mario) Madunic

Quoting David Carlisle <davidc(_at_)nag(_dot_)co(_dot_)uk>:

replace($l_TempString,'&','and')
get an error message stating the & must be followed by an entity
reference


yes, that's not a well formed XML fragment.

replace($l_TempString,'&amp;','and') and

replace($l_TempString,'&amp;amp;','and')

the amp is not replaced.


so presumably $l_TempString does not contain a substring that matches
either "&" or "&amp;".

so what is $l_TempString  ? ie what does <xsl:value-of
select="$l_TempString"/> produce.

It's always helpful to post a complete xml input and complet xslt
stylesheet (in this case, each only need be two or three lines long,


David

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