I just completed your code bit and changed the obvious xsl:result error
into xsl:value-of. But that was not the error you got. I ran it, and it
put out "2".
<?xml version='1.0' encoding='utf-8' ?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="2.0" xmlns:xs="http://www.w3.org/2001/XMLSchema";
xmlns:my="http://whatever"; exclude-result-prefixes="my">
<xsl:function name="my:one">
<xsl:param name="a"/>
<xsl:param name="b"/>
<xsl:value-of select="$a+$b"/>
</xsl:function>
<xsl:template match="/">
<xsl:value-of select="my:one(1,1)"/>
</xsl:template>
</xsl:stylesheet>
What I think is that you accidentally ran an XSLT 2.0 stylesheet with an
XSLT 1.0 processor (which should already complain about the xsl:function
instruction, but perhaps first throws an error about the extension
functions not being known. Saxon for instance says there's no known java
function).
Cheers,
-- Abel Braaksma
Karanam(_dot_)Chowdary(_at_)iflexsolutions(_dot_)com wrote:
The error is "Namespace http://whatever doesn't contain any functions"
-----Original Message-----
From: Abel Braaksma [mailto:abel(_dot_)online(_at_)xs4all(_dot_)nl]
Sent: Wednesday, September 12, 2007 12:14 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] xsl:function
Karanam(_dot_)Chowdary(_at_)iflexsolutions(_dot_)com wrote:
Hello,
I m very new to XSL and XML just strtd working 10 days back.
I hv a problem in using <xsl:function>. What's the name space to be
given? Shud I give a valid name space which contains the functions?
<?xml version='1.0' encoding='utf-8' ?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="2.0" xmlns:xs="http://www.w3.org/2001/XMLSchema";
xmlns:my="http://whatever"; exclude-result-prefixes="my">
<xsl:function name="my:one">
<xsl:param name="a"/>
<xsl:param name="b"/>
<xsl:result select="$a+$b"/>
</xsl:function>
<xsl:template match="/">
<xsl:value-of select="my:one(1,1)"/>
.......
What is the mistake here? Am I missing sumthing?
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