Sujata Gohad wrote:
<xsl:for-each select="locus[position()=1]">
<xsl:text >M </xsl:text >
<xsl:value-of select="@ellipse_x"/ >
<xsl:text > </xsl:text >
<xsl:value-of select="@ellipse_y"/ >
</xsl:for-each >
<xsl:for-each select="locus[position()!=1]">
<xsl:text > L</xsl:text >
<xsl:value-of select="@ellipse_x"/ >
<xsl:text > </xsl:text >
<xsl:value-of select="@ellipse_y"/ >
</xsl:for-each >
Is there a way to faster iteration of the "locus" elements?
See if this is any quicker:
<xsl:for-each select="locus">
<xsl:choose>
<xsl:when test="position() = 1">
<xsl:text>M </xsl:text>
</xsl:when>
<xsl:otherwise>
<xsl:text> L </xsl:text>
</xsl:otherwise>
</xsl:choose>
<xsl:value-of select="@ellipse_x"/ >
<xsl:text > </xsl:text >
<xsl:value-of select="@ellipse_y"/ >
</xsl:for-each>
Depending on your XSLT processor, your original code may be constructing
up to four node-sets: locus, the subset when position() = 1, locus
(again), the subset when position() != 1.
You're allowed to use position() in almost any expression, not just as
the predicate of a prior selection. In my code, position() applies to
the position that each locus has in the most recent for-each, which is
what you want.
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