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Re: [xsl] Enclosing sequence items in single quotes

2007-10-19 07:56:22
Thanks to Andrew and David.
-- 
Charles Knell
cknell(_at_)onebox(_dot_)com - email



-----Original Message-----
From:     Andrew Welch <andrew(_dot_)j(_dot_)welch(_at_)gmail(_dot_)com>
Sent:     Fri, 19 Oct 2007 15:54:02 +0100
To:       xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject:  Re: [xsl] Enclosing sequence items in single quotes

On 19/10/2007, cknell(_at_)onebox(_dot_)com <cknell(_at_)onebox(_dot_)com> 
wrote:
I need some help in constructing a string from a sequence. Consider this 
template:

<xsl:template match="/">
    <xsl:variable name='pf-codes'><xsl:value-of 
select="position-translation/position/code[(_at_)pf='pf']"/></xsl:variable>
    <xsl:variable name="pf-codes-string" select="for $s in $pf-codes return 
$s"/>
     <xsl:value-of select="$pf-codes-string"/>
</xsl:template>

This produces output like this:

AA BB CC DD EE FF GG ...

I need output like this:

'AA','BB','CC','DD','EE','FF','GG', ..., 'ZZ'

Note that the last item is not followed by a comma.

I haven't moved on to the question of using position()=last() to bring about 
this last requirement.

I'm having trouble constructing an expression that will enclose each item in 
the sequence in quotes (single).

Please point me in the right direction. Thanks

select="string-join($pf-codes/concat('''', ., ''''), ',')"


cheers
-- 
Andrew Welch
http://andrewjwelch.com
Kernow: http://kernowforsaxon.sf.net/

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