In XSLT 2.0, when you do <xsl:value-of select="EXPR"/> and EXPR selects a
sequence of nodes, the output consists of the string-values of those nodes,
separated by a single space.
If you want to copy the nodes to the output rather than extracting their
string values, try <xsl:copy-of>.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Sean Tiley [mailto:sean(_dot_)tiley(_at_)gmail(_dot_)com]
Sent: 18 January 2008 23:46
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] xpath query
Hi there,
I am still struggling with mostof this stuff, but I have a
question related to the original data.
<ROOT>
<LEVEL2>
<B>
<a>100</a>
<b apply="1">100</b>
<c>100</c>
</B>
<C>
<a>100</a>
<b>100</b>
<c apply="1">100</c>
</C>
</LEVEL2>
</ROOT>
If I create the following stylesheet I get 100 100 output
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; version="2.0">
<xsl:template match="ROOT">
<html>
<xsl:value-of select="LEVEL2/*/*[(_at_)apply='1']"/>
</html>
</xsl:template>
</xsl:stylesheet>
What I am not clear on is why does this return values and not nodes?
Or is this really returning both nodes and I am getting the
value of each one because of the <xsl:value-of select="..."/>
expression?
As far as I can figure the expression ROOT/LEVEL2/*/*[(_at_)apply='1']"
says give me the nodes that have the arrtibute apply=1 and
are grandchildren of level2.
I kind of though to get both values I would have to do something like
<xsl:template match="ROOT">
<xsl:for-each select="LEVEL2/*/*[(_at_)apply='1']">
<xsl:value-of select="."/>
</xsl:for-each>
</xsl:template>
Sorry if this seems really trivial but it helps me to better
understand.
--
Thanks
Sean
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