Hi Abel,
No I am not the same person. Why did you think that?
I was reading the thread and was trying to fully understand the
requirement and solutions provided. I used the original XML to play
with creating my stylesheets to see what I could do with it.
Did I do something incorrect when I asked my questions in the same
thread? Should I have posted a new message. Please tell me as I am
new to this list and dont want to make a bad impression.
I do appreciate your comments on my questions, they certainly help me
get all of this straight in my head.
Again thanks.
Sean
On Jan 18, 2008 7:56 PM, Abel Braaksma <abel(_dot_)online(_at_)xs4all(_dot_)nl>
wrote:
Sean Tiley wrote:
Hi there,
I am still struggling with mostof this stuff, but I have a question
related to the original data.
Are you by any chance the same one as the original poster, who posted to
this list with the same subjectline and the same data (going by and
signing by the name "Senthil Nathan R")?
If I create the following stylesheet I get 100 100 output
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="2.0">
<xsl:template match="ROOT">
<html>
<xsl:value-of select="LEVEL2/*/*[(_at_)apply='1']"/>
</html>
</xsl:template>
</xsl:stylesheet>
What I am not clear on is why does this return values and not nodes?
That is why the instruction is called "value-of": that means, like you
said, that it will return values, and not nodes. If you want nodes, you
must use xsl:copy-of instead.
Or is this really returning both nodes and I am getting the value of
each one because of the <xsl:value-of select="..."/> expression?
You are saying it right there. You are getting the "value of" ...
because of using the "value-of" instruction... ;)
As far as I can figure the expression ROOT/LEVEL2/*/*[(_at_)apply='1']"
says give me the nodes that have the arrtibute apply=1 and are
grandchildren of level2.
Yes, that is precisely what the expression says. But you are mixing the
XPath expression and the XSLT instruction here. In XPath you say "give
me those nodes", then you instruct XSLT to use the value of those nodes,
and not the nodes themselves (again, that would be xsl:copy-of).
I kind of though to get both values I would have to do something like
<xsl:template match="ROOT">
<xsl:for-each select="LEVEL2/*/*[(_at_)apply='1']">
<xsl:value-of select="."/>
</xsl:for-each>
</xsl:template>
Sorry if this seems really trivial but it helps me to better understand.
In XSLT 1.0, the first value of a node set was returned, which would be
"100" in your case. In XSLT 2.0 (which is what you are using), this
changed because the underlying model changed: everything is a sequence
now. The resultset of an XPath statement is a sequence of items (nodes,
text nodes, attributes, strings etc) and the value of these items is
taken, and finally these values are separated by whatever is in the
attribute "separator":
<xsl:value-of select="(2 to 10)[. le 5]" separator=":" />
will output the string "2:3:4:5" (i.e., all values lower or equal to
five, separated by the colon).
The for-each is hardly ever necessary and I believe it is often
over-used. Instead of for-each you can just as well use
xsl:apply-templates. There are, however, exceptions (notably: for-each
can work on any item type, whereas apply-templates only works on a
nodeset). Depending on what you want, you are right by your statement
that you need something to iterate over, or apply templates on the nodes
in the set. However, if you only need the first node, you can of course
use the predicate [1], or another number if you do not want the first:
<xsl:value-of select="*[(_at_)apply='1'][1]" />
I think many people find this at first confusing: when do you get a node
set, when do you get one node, when do you get a sequence or a sequence
of nodes, when do you need apply-templates, when for-each or
for-each-group etc etc. Getting it straight is vital for working with
XSLT without frustration.
HTH,
Cheers,
-- Abel Braaksma
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