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RE: [xsl] Slow XSLT

2008-03-12 19:52:28

It is like if I was using [1], [2] to get the current Row 
(Row[1], Row[2]) but the '.' does not work with the node set $set

Is that clearer?

No, I'm sorry, it isn't. Either you want to process the current row, or you
want to process the rows in $set - you keep talking about the "current" Row,
and then saying you don't want the current Row, you want a row in $set. You
can do either, but you seem to be confused about which you want.

Michael Kay
http://www.saxonica.com/


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