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Re: [xsl] XSL/XPath to generate a list of ancestors?

2008-05-12 09:01:17
Have a look at
http://xsltsl.sourceforge.net/node.html
There is template that generates an XPath for a given node.  This is
pretty similar to your desired template.

Darcy
On Mon, May 12, 2008 at 11:51 AM, Nathan Potter
<ndp(_at_)coas(_dot_)oregonstate(_dot_)edu> wrote:

 I need to concatenate the "name" attributes of all of the parents for each
element. All I could figure out was to use a recursive template. Is there a
more straightforward way to accomplish this?



 XML:

 <Dataset name="root">
    <A name="a1">
        <A name="a2">
            <A name="a3" />
        </A>
    </A>
    <B name="b1">
        <B name="b2"/>
    </B>
 </Dataset>

 Desired output:

 <fullName>a1</fullName>
 <fullName>a1.a2</fullName>
 <fullName>a1.a2.a3</fullName>

 <fullName>b1</fullName>
 <fullName>b1.b2</fullName>


 XSL:

    <xsl:template name="fullName">
        <fullName>
            <xsl:call-template name="fullNameWorker" />
        </fullName >
    </xsl:template>

    <xsl:template match="*" name="fullNameWorker" mode="fullName">
        <xsl:if test=".!=/">
            <xsl:apply-templates select=".." mode="fullName"/>
            <xsl:if test="..!=/">.</xsl:if>
            <xsl:value-of select="@name"/>
        </xsl:if>
    </xsl:template>

 ============================================================
 Nathan Potter                 Oregon State University, COAS
 ndp at coas.oregonstate.edu   104 Ocean. Admin. Bldg.
 541 737 2293 voice            Corvallis, OR   97331-5503
 541 737 2064 fax



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