Nathan Potter wrote:
I need to concatenate the "name" attributes of all of the parents for
each element. All I could figure out was to use a recursive template. Is
there a more straightforward way to accomplish this?
XML:
<Dataset name="root">
<A name="a1">
<A name="a2">
<A name="a3" />
</A>
</A>
<B name="b1">
<B name="b2"/>
</B>
</Dataset>
Desired output:
<fullName>a1</fullName>
<fullName>a1.a2</fullName>
<fullName>a1.a2.a3</fullName>
<fullName>b1</fullName>
<fullName>b1.b2</fullName>
So you want to exclude the root element 'Dataset' although it has a name
attribute. Then the following should do:
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="1.0">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="/">
<xsl:apply-templates select="*//*"/>
</xsl:template>
<xsl:template match="*">
<fullName>
<xsl:for-each select="ancestor-or-self::*[not(generate-id() =
generate-id(/*))]/@name">
<xsl:value-of select="."/>
<xsl:if test="position() != last()">
<xsl:text>.</xsl:text>
</xsl:if>
</xsl:for-each>
</fullName>
</xsl:template>
</xsl:stylesheet>
--
Martin Honnen
http://JavaScript.FAQTs.com/
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