I didn't fully read your requirements the first time around, but this
really should be fairly straightforward.
<xsl:template match="*">
<fullName>
<xsl:for-each select="ancestor-or-self::*[parent::*]">
<xsl:value-of select="@name" />
<xsl:if test="position() != last()">.</xsl:if>
</xsl:for-each>
</fullName>
</xsl:template>
~ Scott
-----Original Message-----
From: Scott Trenda [mailto:Scott(_dot_)Trenda(_at_)oati(_dot_)net]
Sent: Monday, May 12, 2008 11:00 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] XSL/XPath to generate a list of ancestors?
<xsl:for-each select="ancestor::*">
<xsl:value-of select="name()" />
</xsl:for-each>
~ Scott
-----Original Message-----
From: Nathan Potter [mailto:ndp(_at_)coas(_dot_)oregonstate(_dot_)edu]
Sent: Monday, May 12, 2008 10:52 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Cc: Nathan Potter
Subject: [xsl] XSL/XPath to generate a list of ancestors?
I need to concatenate the "name" attributes of all of the parents for
each element. All I could figure out was to use a recursive template.
Is there a more straightforward way to accomplish this?
XML:
<Dataset name="root">
<A name="a1">
<A name="a2">
<A name="a3" />
</A>
</A>
<B name="b1">
<B name="b2"/>
</B>
</Dataset>
Desired output:
<fullName>a1</fullName>
<fullName>a1.a2</fullName>
<fullName>a1.a2.a3</fullName>
<fullName>b1</fullName>
<fullName>b1.b2</fullName>
XSL:
<xsl:template name="fullName">
<fullName>
<xsl:call-template name="fullNameWorker" />
</fullName >
</xsl:template>
<xsl:template match="*" name="fullNameWorker" mode="fullName">
<xsl:if test=".!=/">
<xsl:apply-templates select=".." mode="fullName"/>
<xsl:if test="..!=/">.</xsl:if>
<xsl:value-of select="@name"/>
</xsl:if>
</xsl:template>
============================================================
Nathan Potter Oregon State University, COAS
ndp at coas.oregonstate.edu 104 Ocean. Admin. Bldg.
541 737 2293 voice Corvallis, OR 97331-5503
541 737 2064 fax
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