How? The for-each loop works on the input set which never gets as high
as 10 if there aren't enough items in the input set.
-----Original Message-----
From: Colin Paul Adams [mailto:colin(_at_)colina(_dot_)demon(_dot_)co(_dot_)uk]
Sent: Wednesday, October 22, 2008 10:44 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] N input nodes to specific number of ouput nodes
"Chris" == Bordeman, Chris
<Chris(_dot_)Bordeman(_at_)wolterskluwer(_dot_)com>
writes:
Chris> Hi all.
Chris> I need to loop through some nodes and output exactly 10
Chris> output nodes, no matter how many input nodes there are. If
Chris> too few input nodes the ouput will just show "N/A" and if
Chris> too many input nodes they will just be ignored.
Chris> I can do the 'too many' with a for-each and a choose based
Chris> on position() but don't get how the 'too few' scenario is
Chris> handled.
An xsl:choose discriminating on count() should do the trick.
--
Colin Adams
Preston Lancashire
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