"Chris" == Bordeman, Chris
<Chris(_dot_)Bordeman(_at_)wolterskluwer(_dot_)com> writes:
Chris> How? The for-each loop works on the input set which never
Chris> gets as high as 10 if there aren't enough items in the
Chris> input set.
Something like:
<xsl:template match="whatever">
<xsl_variable name="length" select="."/>
<xsl:choose/>
<xsl:when test="count($length) lt 10">
...
<xsl:otherwise>
Chris> -----Original Message----- From: Colin Paul Adams
Chris> [mailto:colin(_at_)colina(_dot_)demon(_dot_)co(_dot_)uk] Sent:
Wednesday, October
Chris> 22, 2008 10:44 AM To:
xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Chris> Subject: Re: [xsl] N input nodes to specific number of
Chris> ouput nodes
"Chris" == Bordeman, Chris
<Chris(_dot_)Bordeman(_at_)wolterskluwer(_dot_)com>
Chris> writes:
Chris> Hi all.
Chris> I need to loop through some nodes and output exactly 10
Chris> output nodes, no matter how many input nodes there are. If
Chris> too few input nodes the ouput will just show "N/A" and if
Chris> too many input nodes they will just be ignored.
Chris> I can do the 'too many' with a for-each and a choose based
Chris> on position() but don't get how the 'too few' scenario is
Chris> handled.
Chris> An xsl:choose discriminating on count() should do the
Chris> trick. -- Colin Adams Preston Lancashire
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Colin Adams
Preston Lancashire
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