thanks all for the help,
based on the first answer from ken, i'm doing the following
which does exactly what i want
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:skos="http://www.w3.org/2004/02/skos/core#";
version="1.0">
<xsl:template
match="skos:prefLabel|skos:altLabel|skos:hiddenLabel|skos:definition|skos:scopeNote[not(@xml:lang)]">
<xsl:copy>
<xsl:attribute name="xml:lang">en</xsl:attribute>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="@*|node()"><!--identity for all other nodes-->
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
wkr www.turnguard.com
----- Original Message -----
From: "Syd Bauman" <Syd_Bauman(_at_)Brown(_dot_)edu>
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Sent: Thursday, October 15, 2009 2:39:48 AM GMT +01:00 Amsterdam / Berlin /
Bern / Rome / Stockholm / Vienna
Subject: RE: [xsl] Change xml:lang of a skos:prefLabel [ skos, rdf, xml:lang ]
<xsl:template match="skos:altLabel|skos:prefLabel">
<xsl:copy>
<xsl:attribute name="xml:lang">en</xsl:attribute>
<xsl:copy-of select="@*"/>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="*">
<xsl:copy>
<xsl:copy-of select="@*"/>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
This relies on the fact that if you add the same attribute to an element
twice, the last one wins.
1) Is that true for both XSLT 1 and 2 ?
2) No disrespect intended, but something looks amiss here to me. I
notice there is a separate <copy-of> for the attributes, but then
templates are applied for the attributes, too. And what does a <copy-of>
that's a child of <copy> do, anyway?
Ah. To answer my own question, I just ran a tiny stylesheet with
the above identity template on itself, and got the following result.
--------- output of this stylesheet on itself ---------
<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="1.0">1.0
<xsl:template match="/">/
<xsl:apply-templates select="node()">node()</xsl:apply-templates>
</xsl:template>
<xsl:template match="*">*
<xsl:copy>
<xsl:copy-of select="@*">@*</xsl:copy-of>
<xsl:apply-templates select="@*|node()">@*|node()</xsl:apply-templates>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
--------- end output ---------
So I think that's not what M. Kay meant -- I suspect the <copy-of>
is a holdover from a previous version or a copy-and-paste error or
some such.
Either that or I've missed something, in which case I'm hoping
someone explains it!
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