Re: [xsl] Transforming xml with any namespace2009-11-25 09:25:35Anders Viklund wrote: <xsl:template match="//*[local-name()='Type1']"> You can use the XPath 2.0 namespace wildcard: <xsl:template match="*:Type1"> -- Florent Georges http://www.fgeorges..org/ --~------------------------------------------------------------------ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/ or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com> --~--
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