Ok, changed to XSLT 2.0, but still the same problem...
XSL:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; version="2.0">
<xsl:output method="text" />
<xsl:template match="/">
<xsl:apply-templates/>
</xsl:template>
<xsl:template match="*:Type1">
<xsl:value-of select="local-name(.)"/> <xsl:text
disable-output-escaping="yes">=</xsl:text> <xsl:value-of select="."/>
</xsl:template>
</xsl:stylesheet>
OUTPUT:
Type1=value1
Type1=value2
please dont print me
----------------------------------------
Date: Wed, 25 Nov 2009 14:25:11 +0000
From: lists(_at_)fgeorges(_dot_)org
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Transforming xml with any namespace
Anders Viklund wrote:
You can use the XPath 2.0 namespace wildcard:
--
Florent Georges
http://www.fgeorges..org/
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