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Re: [xsl] sequential numbering in xslt

2010-01-04 11:52:49

another XML format using XSLT. The output XML file has a schema and
has a required 'seq' attribute in the root element that needs to be
incremented for each input XML file.
...
for every input file, in the transformation, I want to increment
attribute 'seq' in the output file by 1 when I transform the input
files using xslt.
I  have tried <xsl:number> and tried writing a function. But the
problem is that since variables in xslt are constants, there is no way
to increment a number, store it in a temp variable and increment it
for the next time in xslt 2.0 unlike procedural languages like C or
C++.

Is there any other way of achieving this in XSLT 2.0?

Using position() is one option, keeping track of the number of
documents you are processing yourself, using a recursive template,
is another:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0"
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform";

  xmlns:xs="http://www.w3.org/2001/XMLSchema";
  
  exclude-result-prefixes="xs">

  <!-- URI approporiate for fn:collection, e.g., in
       saxon:

       <collection stable="true">
         <doc href="file1.xml" />
         <doc href="file2.xml" />
         <doc href="file3.xml" />
       </collection>
  -->
  <xsl:param name="collection-href" required="yes" />

  <!-- Previous sequence number, if we need to start at
       some point other than 1. -->
  <xsl:param name="previous-number" select="0" />


  <xsl:template match="/">
    <xsl:call-template name="example">
      <xsl:with-param name="documents" select="collection($collection-href)" />
      <xsl:with-param name="previous-number" select="$previous-number" />
    </xsl:call-template>
  </xsl:template>

  <xsl:template name="example">
    <xsl:param name="documents" />
    <xsl:param name="previous-number" required="yes" />

    <xsl:if test="$documents[1]">
      <xsl:variable name="current-number" as="xs:integer" 
select="xs:integer($previous-number+1)" />

      <!-- Here we could use xsl:result-document and xsl:apply-templates
           to kick off processing of our input document. -->
      <example seq="{$current-number}" />

      <!-- Now we recursively process the next document in our list -->
      <xsl:call-template name="example">
        <xsl:with-param name="documents" select="remove($documents, 1)" />
        <xsl:with-param name="previous-number" select="$current-number" />
      </xsl:call-template>
    </xsl:if>

    <!-- Here, if not($documents), we could write out our
         last number to some file that we use to track our
         sequence number across time. -->
  </xsl:template>

</xsl:stylesheet>

Running this w/ the example collection document and no override
of $previous-number would produce

<example seq="1"/>
<example seq="2"/>
<example seq="3"/>

whereas setting $previous-number to 3 would produce

<example seq="4"/>
<example seq="5"/>
<example seq="6"/>


Jim

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
James A. Robinson                       
jim(_dot_)robinson(_at_)stanford(_dot_)edu
Stanford University HighWire Press      http://highwire.stanford.edu/
+1 650 7237294 (Work)                   +1 650 7259335 (Fax)

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