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Re: [xsl] sequential numbering in xslt

2010-01-11 14:11:08
Hi

I tried to implement this solution for my program.

Here is what I did. I have a folder with xml files. I used
collection() to point to that folder. But the problem I am having is
that reading the xml files one by one. When I say $document[1], it
considers all files as $documents[1].

So my output files end up like this:

If I have 2  XML files inside the folder and I run my trasnformation
using saxon9.1, I get back the two xml files as output but the @seq is
as shown:

1st XML file;

<car seq="12">
<req>....<req>

<body id="c1">

</body>

</car>

2nd XML file:

<car seq="12">
<req>....<req>

<body id="c1">

</body>

</car>

Can you please tell me what I am doing wrong here?


On Mon, Jan 4, 2010 at 11:52 AM, James A. Robinson
<jim(_dot_)robinson(_at_)stanford(_dot_)edu> wrote:

another XML format using XSLT. The output XML file has a schema and
has a required 'seq' attribute in the root element that needs to be
incremented for each input XML file.
...
for every input file, in the transformation, I want to increment
attribute 'seq' in the output file by 1 when I transform the input
files using xslt.
I  have tried <xsl:number> and tried writing a function. But the
problem is that since variables in xslt are constants, there is no way
to increment a number, store it in a temp variable and increment it
for the next time in xslt 2.0 unlike procedural languages like C or
C++.

Is there any other way of achieving this in XSLT 2.0?

Using position() is one option, keeping track of the number of
documents you are processing yourself, using a recursive template,
is another:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform";

 xmlns:xs="http://www.w3.org/2001/XMLSchema";

 exclude-result-prefixes="xs">

 <!-- URI approporiate for fn:collection, e.g., in
      saxon:

      <collection stable="true">
        <doc href="file1.xml" />
        <doc href="file2.xml" />
        <doc href="file3.xml" />
      </collection>
 -->
 <xsl:param name="collection-href" required="yes" />

 <!-- Previous sequence number, if we need to start at
      some point other than 1. -->
 <xsl:param name="previous-number" select="0" />


 <xsl:template match="/">
   <xsl:call-template name="example">
     <xsl:with-param name="documents" select="collection($collection-href)" />
     <xsl:with-param name="previous-number" select="$previous-number" />
   </xsl:call-template>
 </xsl:template>

 <xsl:template name="example">
   <xsl:param name="documents" />
   <xsl:param name="previous-number" required="yes" />

   <xsl:if test="$documents[1]">
     <xsl:variable name="current-number" as="xs:integer" 
select="xs:integer($previous-number+1)" />

     <!-- Here we could use xsl:result-document and xsl:apply-templates
          to kick off processing of our input document. -->
     <example seq="{$current-number}" />

     <!-- Now we recursively process the next document in our list -->
     <xsl:call-template name="example">
       <xsl:with-param name="documents" select="remove($documents, 1)" />
       <xsl:with-param name="previous-number" select="$current-number" />
     </xsl:call-template>
   </xsl:if>

   <!-- Here, if not($documents), we could write out our
        last number to some file that we use to track our
        sequence number across time. -->
 </xsl:template>

</xsl:stylesheet>

Running this w/ the example collection document and no override
of $previous-number would produce

<example seq="1"/>
<example seq="2"/>
<example seq="3"/>

whereas setting $previous-number to 3 would produce

<example seq="4"/>
<example seq="5"/>
<example seq="6"/>


Jim

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
James A. Robinson                       
jim(_dot_)robinson(_at_)stanford(_dot_)edu
Stanford University HighWire Press      http://highwire.stanford.edu/
+1 650 7237294 (Work)                   +1 650 7259335 (Fax)

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