[xsl] Why does the addition of one (1) to a positiveInteger produce an i

Hi Folks,

I have a function that has a parameter with a xs:positiveInteger datatype. 
Within the function I add one (1) to the parameter:

<xsl:function name="f:iter">
    <xsl:param name="count" as="xs:positiveInteger" />

    ...

    <xsl:sequence select="f:iter($count + 1)" />

</xsl:function>

When I run this I get an error, "The argument to f:iter is xs:positiveInteger, 
the supplied value is xs:integer"

What is the rationale for this? After all, if I add one (1) to any 
positiveInteger the result must be a positiveInteger.

/Roger

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