At 2010-08-29 15:43 -0400, Costello, Roger L. wrote:
I have a function that has a parameter with a xs:positiveInteger
datatype. Within the function I add one (1) to the parameter:
<xsl:function name="f:iter">
<xsl:param name="count" as="xs:positiveInteger" />
...
<xsl:sequence select="f:iter($count + 1)" />
</xsl:function>
When I run this I get an error, "The argument to f:iter is
xs:positiveInteger, the supplied value is xs:integer"
What is the rationale for this? After all, if I add one (1) to any
positiveInteger the result must be a positiveInteger.
False. An integer *type* is more general than the positiveInteger
*type*, thus when you add the two the result is the more general of
the two, which is integer. And since the integer is too general for
the parameter type, there is the error.
So, not only do you need:
<xsl:sequence select="f:iter($count + xs:positiveInteger(1))" />
.... but wherever you are calling f:iter() for the first time, if you
are doing:
<xsl:value-of select="f:iter(3)"/>
.... you will get the same problem and you need to say:
<xsl:value-of select="f:iter(xs:positiveInteger(3))"/>
I hope this helps.
. . . . . . . . . . Ken
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