When I run this I get an error, "The argument to f:iter is xs:positiveInteger, the
supplied value is xs:integer"
What is the rationale for this? After all, if I add one (1) to any
positiveInteger the result must be a positiveInteger.
There might be logic for saying that the result of xs:positiveInteger +
xs:positiveInteger should always be xs:positiveInteger, but a rule that
says xs:positiveInteger + xs:integer gives xs:positiveInteger provided
that the xs:integer is positive (or provided it is greater than the
negation of the first argument?) would be rather arbitrary.
Generally I would advise against writing a function that expects
subtypes of xs:integer as an argument, because you will never be able to
supply the argument as a simple literal. These types were designed for
validation, not for type-checking programs. That's why, for example, the
standard functions insert() and remove() declare the expected type as
xs:integer rather than xs:positiveInteger. (It's also why in XSLT 2.0
types such as xs:positiveInteger were excluded from the set of types
recognized by a basic XSLT processor). If you want to reject negative
integers, do it by conditional code in the body of the function, not by
means of the type signature.
Michael Kay
Saxonica
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