Thank you! I have modified your suggestions to sort of work. The code is below.
I need to carry to the result tree, the siblings that fall in the current
section. I know i need something along the lines of following-sibling: up to
next section. Or is there another way to get those in this algorithm.
The current line only get all siblings but the headings.
Any suggestions?
Thank you so much!
Russ
<?xml version='1.0'?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version='2.0' xmlns:xs="http://www.w3.org/2001/XMLSchema">
<xsl:template name="process-level">
<xsl:param name="population" required="yes" as="element()*"/>
<xsl:param name="level" required="yes" as="xs:integer"/>
<xsl:for-each-group select="$population"
group-starting-with="section[xs:integer(@level) eq $level]">
<xsl:element name="Subsection">
<xsl:value-of select="@level"/>
<!-- I know this line needs to be changed to get the siblings up to the next
section element. -->
<xsl:copy-of select="following-sibling::*[name()!='section']"/>
<xsl:call-template name="process-level">
<xsl:with-param name="population"
select="current-group()[position() != 1]"/>
<xsl:with-param name="level"
select="$level + 1"/>
</xsl:call-template>
</xsl:element>
</xsl:for-each-group>
</xsl:template>
<xsl:template match="article">
<xsl:call-template name="process-level">
<xsl:with-param name="population" select="./section"/>
<xsl:with-param name="level" select="2"/>
</xsl:call-template>
</xsl:template>
</xsl:stylesheet>
The elegant algorithm IS a recursive routine with a named template: see
http://www.saxonica.com/papers/ideadb-1.1/mhk-paper.xml
for a solution of a similar problem (Stage Two is the relevant part)
Michael Kay
Saxonica
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