When you are processing level 4, and the next level is 5, you have a
sequence something like this
S4 x x x x S5 x x x S5 x x x S5 x x x
You take everything except the leading S4 - that is,
current-group()[position() gt 1], and feed this to the next level of
grouping. This does group-starting-with = S5. The first group contains
the initial (x x x x) that followed the S4; the subsequent groups each
start with an S5. You want to output the initial (x x x x) unchanged,
but wrap the other groups in a section element. The logic is
<xsl:for-each-group group-starting-with="S5">
<xsl:choose>
<xsl:when test="current-group()[1] is an element that does not match S5">
<xsl:copy-of select="current-group()"/>
</
<xsl:otherwise>
<section level="5">
recurse, select="current-group()[position() gt 1]"
</
<
</
</
I hope this gives the idea.
Michael Kay
Saxonica
On 23/09/2010 10:53 PM, russurquhart1(_at_)verizon(_dot_)net wrote:
Thank you! I have modified your suggestions to sort of work. The code is below.
I need to carry to the result tree, the siblings that fall in the current
section. I know i need something along the lines of following-sibling: up to
next section. Or is there another way to get those in this algorithm.
The current line only get all siblings but the headings.
Any suggestions?
Thank you so much!
Russ
<?xml version='1.0'?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version='2.0' xmlns:xs="http://www.w3.org/2001/XMLSchema">
<xsl:template name="process-level">
<xsl:param name="population" required="yes" as="element()*"/>
<xsl:param name="level" required="yes" as="xs:integer"/>
<xsl:for-each-group select="$population"
group-starting-with="section[xs:integer(@level) eq $level]">
<xsl:element name="Subsection">
<xsl:value-of select="@level"/>
<!-- I know this line needs to be changed to get the siblings up to the next
section element. -->
<xsl:copy-of select="following-sibling::*[name()!='section']"/>
<xsl:call-template name="process-level">
<xsl:with-param name="population"
select="current-group()[position() != 1]"/>
<xsl:with-param name="level"
select="$level + 1"/>
</xsl:call-template>
</xsl:element>
</xsl:for-each-group>
</xsl:template>
<xsl:template match="article">
<xsl:call-template name="process-level">
<xsl:with-param name="population" select="./section"/>
<xsl:with-param name="level" select="2"/>
</xsl:call-template>
</xsl:template>
</xsl:stylesheet>
The elegant algorithm IS a recursive routine with a named template: see
http://www.saxonica.com/papers/ideadb-1.1/mhk-paper.xml
for a solution of a similar problem (Stage Two is the relevant part)
Michael Kay
Saxonica
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