Not sure if you are using XSLT 2 or are restricted to XSLT 1. The
following XSLT 1 seems to work with rudimentary tests. The idea is
simple: when you hit a text node that is both immediately before
(after) an element for which we plan to add brackets AND it ends in
(starts with) a square bracket, write out the text node without the
offending bracket.
<xsl:template
match="text()[following-sibling::node()[1][self::citationref]][substring(.,string-length(.),1)='[']">
<xsl:value-of select="substring(.,1,string-length(.)-1)"/>
</xsl:template>
<xsl:template
match="text()[preceding-sibling::node()[1][self::citationref]][substring(.,1,1)=']']">
<xsl:value-of select="substring(.,2)"/>
</xsl:template>
Others on this list may be able to provide you with better, or at
least prettier, versions of that. And certainly it's a lot nicer if
you're using XSLT 2. (Although you have to mind your escaping of
square bracket, a special character to the regular expression
language XSLT uses.)
Hi Team,
Is there any logic by which duplicate squire bracket can be avoided
([<xref><sup>[2]</sup></xref>]) . Below are input and output
XSLT:
<xsl:template match="citationref">
<xref>
<xsl:attribute name="rid"><xsl:value-of
select="@linkend"/></xsl:attribute>
<xsl:attribute name="ref-type">bibr</xsl:attribute>
<sup>
<xsl:text>[</xsl:text>
<xsl:apply-templates/>
<xsl:text>]</xsl:text>
</sup>
</xref>
</xsl:template>
Input:
<para>Once ... <citationref linkend="cit379-1">1</citationref>. The
...[<citationref linkend="cit379-2">2</citationref>].</p>
Output:
<p>Once ... <xref rid="cit379-1" ref-type="bibr"><sup>[1]</sup></xref>. The
...[<xref rid="cit379-2" ref-type="bibr"><sup>[2]</sup></xref>].</para>
Required Output:
<p>Once ... <xref rid="cit379-1" ref-type="bibr"><sup>[1]</sup></xref>. The
...<xref rid="cit379-2" ref-type="bibr"><sup>[2]</sup></xref>.</p>
BTW, I hope that you mean <para> and </para> OR <p> and </p> in all
cases ... this is not well-formed as it sits.
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