Seems good!!! But are not able to integrate it within my existing template.
I am using below for para element.
<xsl:template match="para">
<p>
<xsl:call-template name="id"/>
<xsl:apply-templates/>
</p>
</xsl:template>
-----Original Message-----
From: Syd Bauman [mailto:Syd_Bauman(_at_)Brown(_dot_)edu]
Sent: Tuesday, March 22, 2011 5:02 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Squire bracket is getting duplicate.
Not sure if you are using XSLT 2 or are restricted to XSLT 1. The following
XSLT 1 seems to work with rudimentary tests. The idea is
simple: when you hit a text node that is both immediately before
(after) an element for which we plan to add brackets AND it ends in (starts
with) a square bracket, write out the text node without the offending
bracket.
<xsl:template
match="text()[following-sibling::node()[1][self::citationref]][substring(.,s
tring-length(.),1)='[']">
<xsl:value-of select="substring(.,1,string-length(.)-1)"/>
</xsl:template>
<xsl:template
match="text()[preceding-sibling::node()[1][self::citationref]][substring(.,1
,1)=']']">
<xsl:value-of select="substring(.,2)"/>
</xsl:template>
Others on this list may be able to provide you with better, or at least
prettier, versions of that. And certainly it's a lot nicer if you're using
XSLT 2. (Although you have to mind your escaping of square bracket, a
special character to the regular expression language XSLT uses.)
Hi Team,
Is there any logic by which duplicate squire bracket can be avoided
([<xref><sup>[2]</sup></xref>]) . Below are input and output
XSLT:
<xsl:template match="citationref">
<xref>
<xsl:attribute name="rid"><xsl:value-of
select="@linkend"/></xsl:attribute>
<xsl:attribute name="ref-type">bibr</xsl:attribute>
<sup>
<xsl:text>[</xsl:text>
<xsl:apply-templates/>
<xsl:text>]</xsl:text>
</sup>
</xref>
</xsl:template>
Input:
<para>Once ... <citationref linkend="cit379-1">1</citationref>. The
...[<citationref linkend="cit379-2">2</citationref>].</p>
Output:
<p>Once ... <xref rid="cit379-1"
ref-type="bibr"><sup>[1]</sup></xref>. The ...[<xref rid="cit379-2"
ref-type="bibr"><sup>[2]</sup></xref>].</para>
Required Output:
<p>Once ... <xref rid="cit379-1"
ref-type="bibr"><sup>[1]</sup></xref>. The ...<xref rid="cit379-2"
ref-type="bibr"><sup>[2]</sup></xref>.</p>
BTW, I hope that you mean <para> and </para> OR <p> and </p> in all cases
... this is not well-formed as it sits.
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