With xpath++ based on xsltproc and EXSLT this can be done similar:
$ xpath++ "normalize-space(str:concat((//author|//person)/text()))!=''"
author.xml
true
$
Mit besten Gruessen / Best wishes,
Hermann Stamm-Wilbrandt
Level 3 support for XML Compiler team, Fixpack team lead
WebSphere DataPower SOA Appliances
https://www.ibm.com/developerworks/mydeveloperworks/blogs/HermannSW/
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From: "G. Ken Holman" <gkholman(_at_)CraneSoftwrights(_dot_)com>
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com,
Date: 11/03/2011 07:53 PM
Subject: Re: [xsl] XPath which tests that an element does not have mixed
content?
At 2011-11-03 18:44 +0000, Costello, Roger L. wrote:
Would you please recommend an XPath expression which ensures that
the content of <author> is optional whitespace, <Person>, optional
whitespace, and nothing else:
<author>
<Person>
<name>Simon L. Peyton Jones</name>
</Person>
</author>
The result of the XPath expression is true if the content is as
desired and false otherwise. The XPath should return true for the
above example and false for the below example:
<author>
The person is:
<Person>
<name>Simon L. Peyton Jones</name>
</Person>
</author>
In XSLT 2.0 you could test the join of text() children of the cited
elements along the lines of:
not(normalize-space( string-join( (author,Person)/text() ),'')))
I hope this helps.
. . . . . . . . . . Ken
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