At 2013-10-09 21:38 -0700, you wrote:
Just curious how other's might approach a test to determine if the
current node is *not* an only child. This works fine but it feels a
little heavy to me. Thoughts?
<xsl:if test="(count(preceding-sibling::*) +
count(following-sibling::*)) > 1">
<hr/>
</xsl:if>
I think you need "... >0" in your test above to know that the current
element has no siblings.
But if you know your current node is an element you could ask:
test="count(../*)!=1"
... which would return true if the current element is not an only
child element.
I hope this helps.
. . . . . . Ken
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