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Re: [xsl] Only child test

2013-10-10 09:07:58
../*[2]

This is the  first expression I thought about -- then saw that
Вячеслав Седов has already offered it.

Cheers,
Dimitre

On Wed, Oct 9, 2013 at 9:38 PM, Karl Stubsjoen <kstubs(_at_)gmail(_dot_)com> 
wrote:
Just curious how other's might approach a test to determine if the
current node is *not* an only child. This works fine but it feels a
little heavy to me.  Thoughts?

                <xsl:if test="(count(preceding-sibling::*) +
count(following-sibling::*)) &gt; 1">
                    <hr/>
                </xsl:if>

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-- 
Cheers,
Dimitre Novatchev
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Truly great madness cannot be achieved without significant intelligence.
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