count(../* gt 1)
or if you know that you're processing all siblings at the time,
last() gt 1
Michael Kay
Saxonica
On 10 Oct 2013, at 05:38, Karl Stubsjoen wrote:
Just curious how other's might approach a test to determine if the
current node is *not* an only child. This works fine but it feels a
little heavy to me. Thoughts?
<xsl:if test="(count(preceding-sibling::*) +
count(following-sibling::*)) > 1">
<hr/>
</xsl:if>
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