It's traversing the subtree rooted at $n that's not an inspection
operation; this requires access to the nodes under $n, so it would be
an absorption operation. So from context $n, count($n/some/path) is
not going to be streamable unless we allow it to "absorb" $n in doing
so -- not because of the count(), but because of the traversal.
My reading of it so far suggests that count($n/some/path) would be
"striding" and therefore streamable.
It would only be "absorbing" if you materialised the contents of <path>.
--
Andrew Welch
http://andrewjwelch.com
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