This seems to work:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
exclude-result-prefixes="xs"
version="2.0">
<xsl:template match="/">
<xsl:variable name="doc" as="document-node()">
<xsl:document>
<root>
<a>
<c>
<b>This is b 1</b>
</c>
<d>This is d</d>
</a>
<f>
<c>
<b>This is b 2</b>
</c>
</f>
</root>
</xsl:document>
</xsl:variable>
<xsl:variable name="A" as="element()" select="$doc/*/a"/>
<xsl:variable name="B1" as="element()" select="$doc/*/a/c/b"/>
<xsl:variable name="B2" as="element()" select="$doc/*/f/c/b"/>
<result>
<test>b1 in A: <xsl:value-of select="$B1/ancestor::* = $A"/></test>
<test>b2 in A: <xsl:value-of select="$B2/ancestor::* = $A"/></test>
</result>
</xsl:template>
</xsl:stylesheet>
Produces:
<result>
<test>b1 in A: true</test>
<test>b2 in A: false</test>
</result>
Cheers,
E.
--
Eliot Kimber
http://contrext.com
On 6/14/18, 7:22 AM, "Costello, Roger L. costello(_at_)mitre(_dot_)org"
<xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com> wrote:
Hi Folks,
The variable $A contains an element.
The variable $B contains an element.
I need an XPath expression that determines if $B is not contained in $A.
This XPath expression seems to work:
not(index-of($B/ancestor::*,$A))
but that seems awful, i.e., not straightforward, convoluted, and probably
inefficient.
Is there a better (simpler, straightforward, efficient) XPath expression?
/Roger
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