Re: [xsl] Need an XPath expression for: $B is not contained in $A

On 14.06.2018 15:23, Eliot Kimber ekimber(_at_)contrext(_dot_)com wrote:
> This seems to work:
>
> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
>    xmlns:xs="http://www.w3.org/2001/XMLSchema";
>    exclude-result-prefixes="xs"
>    version="2.0">
>    <xsl:template match="/">
>      <xsl:variable name="doc" as="document-node()">
>        <xsl:document>
>        <root>
>          <a>
>            <c>
>              <b>This is b 1</b>
>            </c>
>            <d>This is d</d>
>          </a>
>          <f>
>            <c>
>              <b>This is b 2</b>
>            </c>
>          </f>
>        </root>
>        </xsl:document>
>      </xsl:variable>
>      
>      <xsl:variable name="A" as="element()" select="$doc/*/a"/>
>      <xsl:variable name="B1" as="element()" select="$doc/*/a/c/b"/>
>      <xsl:variable name="B2" as="element()" select="$doc/*/f/c/b"/>
>      <result>
>        <test>b1 in A: <xsl:value-of select="$B1/ancestor::* = $A"/></test>
>        <test>b2 in A: <xsl:value-of select="$B2/ancestor::* = $A"/></test>
Comparing the string value with "=" does not compare the node identity 
so I don't think this is a good idea, unless textual equality is sought.
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