Re: [xsl] XSLT repetition constructs

Because if $a is an empty sequence (which is the situation on the first call), 
then $a[last()] is an empty sequence, and ($x + ()) returns an empty sequence, 
not $x.

Michael Kay
Saxonica

> On 8 Mar 2019, at 05:35, Mukul Gandhi gandhi(_dot_)mukul(_at_)gmail(_dot_)com 
> <xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com> wrote:
>
> Hi Mike,
>
> On Thu, Mar 7, 2019 at 8:49 PM Michael Kay mike(_at_)saxonica(_dot_)com 
> <mailto:mike(_at_)saxonica(_dot_)com> 
> <xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com 
> <mailto:xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com>> wrote:
> Your solution could be rewritten
>
> fold-left($x, (), function($a, $b) {$a, ($a[last()], 0)[1] + $b})
>
> I can confirm that, above expression evaluates correctly.
>
> But why does the following doesn't give the correct answer ?
>
> <xsl:variable name="inpValues" select="(1,2,3,4)" as="xs:integer*"/>
> fold-left($inpValues, (), function($a, $b) {$a, $a[last()] + $b})
>
> i.e why can't $a[last()] work instead your's ($a[last()], 0)[1]  ?
>
>  
>
>
> -- 
> Regards,
> Mukul Gandhi
> XSL-List info and archive <http://www.mulberrytech.com/xsl/xsl-list>
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