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Re: [xsl] XSLT repetition constructs

2019-03-08 03:42:35
from [Mukul Gandhi gandhi(_dot_)mukul(_at_)gmail(_dot_)com] [Permanent Link] 
On Fri, Mar 8, 2019 at 2:10 PM Michael Kay mike(_at_)saxonica(_dot_)com <
xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com> wrote:


Because if $a is an empty sequence (which is the situation on the first
call), then $a[last()] is an empty sequence, and ($x + ()) returns an empty
sequence, not $x.



Thanks, for the explanation.

I came up with following as well, which works (though may be inefficient)

<xsl:variable name="inpValues" select="(1,2,3,4)" as="xs:integer*"/>

fold-left($inpValues, (), function($a, $b) {$a, sum(for $idx in 1 to
count($a) return $inpValues[$idx]) + $b})




-- 
Regards,
Mukul Gandhi
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